WebJul 17, 2014 · 25 n = (5 X 5) n If we raise 5 to any power ,unit digit will only be 5 . For any natural number to end with 0 , it must be a factor of 10 so it must have factors both 2 and 5 .But 25 does not have 2 as a factor. Thus 25 n cannot end with 0 for any natural number n Hope this would have cleared your doubt . WebSolution. If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so 2 & 3 is only prime in the factorization of 6 n. Since 5 is not present in the prime factorization, there is no natural ...
Show that `12^n` cannot end with the digits `0` or `5` for any …
WebMar 29, 2024 · Let us take the example of a number which ends with the digit 0 So, 10 = 2 5 100 = 2 2 5 5 Here we note that numbers ending with 0 has both 2 and 5 as their prime … fans grinding against radiator pc
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WebOct 10, 2024 · If 12 n ends with the digit zero it must be divisible by 5. This is possible only if the prime factorisation of 12 n contains the prime number 5. The prime factorisation of 12 … WebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This … WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be … fan shackle